Question

Moment of inertia of a circular wire of mass $M$ and radius $R$ about its diameter is:

• A. $\frac{M{R}^2}{2}$
• B. $M{R}^2$
• C. $2M{R}^2$
• D. $\frac{M{R}^2}{4}$

Answer 1

The correct option is A $\frac{M{R}^2}{2}$

The moment of Inertia of circular wire about axis passing through its center and perpendicular to its plane is $M{R}^2$.

Using the perpendicular axis theorem, the MI about the axis passing through its diameter is $M{R}^2/2$