Moment of inertia of a hollow sphere of mass M and diameter D about its diameter

M D^{2} / 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 M D^{2} / 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M D^{2} / 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 M D^{2} / 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $M D^{2} / 6$
Moment of inertia of a hollow sphere of mass M and diameter D about its diameter is 2MR²/3
Since, R = D/2, putting the value of R in the above formula,
I = 2 M D²/ 4 x 3 = MD²/6
So, the correct answer is 'MD²/6'

Suggest Corrections

Similar questions

The moment of Inertia of a uniform hollow sphere of mass $M$ and radius $R$ , about its diameter is $\frac{2}{3} M R^{2}$ .

Two discs, each of mass M and radius R is placed parallel to each other at a distance d about a common axis as shown in the figure. The moment of inertia of the system about $Y Y^{'}$ axis.

What is the moment of Inertia of a uniform hollow sphere of mass $M$ and radius $R$ , about its diameter

Q. A hollow sphere of mass 50 kg and radius 5m is rotated about one of its diameter. What will be the rotational inertia of hollow sphere about this axis?

Q. A hollow sphere of mass 50 kg and radius 5 cm is rotated about one of its diameter. The rotational inertia of hollow sphere about this axis is.

Join BYJU'S Learning Program

Moment of inertia of a hollow sphere of mass M and diameter D about its diameter

The correct option is C MD2/6Moment of inertia of a hollow sphere of mass M and diameter D about its diameter is 2MR2/3Since, R = D/2, putting the value of R in the above formula,I = 2 M D2/ 4 x 3 = MD2/6So, the correct answer is 'MD2/6'

The correct option is C $M D^{2} / 6$
Moment of inertia of a hollow sphere of mass M and diameter D about its diameter is 2MR²/3
Since, R = D/2, putting the value of R in the above formula,
I = 2 M D²/ 4 x 3 = MD²/6
So, the correct answer is 'MD²/6'