Moment of inertia of a ring of radius ′r′m about an axis passing through the COM, perpendicular to its plane is Ikg-m2. The moment of inertia of the same ring about an axis passing through the diameter of the ring is nIkg-m2. Find the value of n.
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Solution
Given, ICOM=Ikg-m2 Using perpendicular axis theorem, Idia=ICOM2=I2=0.5Ikg-m2 ∴n=0.5