Question

Moment of inertia of rod about an axis perpendicular to its and passing through its centre is equal to ML^2/2 . Find moment of inertia of rod about an axis perpendicular to its passing through its 1 end.

Answer 1

Dear Student,


$$\begin{gathered} useparallelaxistheorem. \\ MI=\frac{M{L}^2}{2}+M{\left(\frac{L}{2}\right)}^2=\frac{M{L}^2}{2}+\frac{M{L}^2}{4}=\frac{3M{L}^2}{4} \\ REgards \end{gathered}$$