Question

Moment of inertia of solid hemisphere of mass M and radius R about an axis passing through centre of mass as shown, is

• A. $\frac{83}{320}M{R}^2$
• B. $\frac{85}{375}M{R}^2$
• C. $\frac{73}{360}M{R}^2$
• D. $\frac{83}{260}M{R}^2$

Answer 1

The correct option is A $\frac{83}{320}M{R}^2$

$I_1=I_{cm}+M{x}^2$

$\frac{2}{5}M{R}^2=I_{cm}+M{\left(\frac{3}{8}R\right)}^2$

$I_{cm}=\frac{2}{5}M{R}^2-\frac{9}{64}M{R}^2$

$I_{cm}=\frac{83}{320}M{R}^{2}2$