Monochromatic light of frequaency 6×1014 Hz is produced by a laser. The power emitted is 2×10−3 W. The number of photons emitted, on the average, by the sources per second is
A
5×1014
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B
5×1015
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C
5×1016
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D
5×1017
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Solution
The correct option is B5×1015 Energy of incident photon E=hν=6.6×10−34×6×1014=3.96×10−19J Number of photons per second N=PE ⟹N=2×10−33.96×10−19=5×1015 photons/second Correct answer is option B.