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Question

Monochromatic light of frequency 6.0×1014 Hz is produced by a laser. The power emitted is 2×103W. The number of photons emitted, on the average, by the source per second is:

A
5×1014
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B
5×1015
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C
5×1016
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D
5×1017
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Solution

The correct option is B 5×1015
No. of photoelectrons emitted, n=phv.=2×1036.62×1034×6×1014=5×1015

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