Monochromatic light of wavelength $632.8$ nm is produced by a helium-neon laser. The power emitted is $9.42 m W$ .
How fast does a hydrogen atom have to travel in order to have the same momentum as that of the photon?

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Solution

Given $1 a . m . u . = 1.66 \times 10^{- 27}, P_{H} = 1.046 \times 10^{- 27}$
The required speed of the hydrogen atom,
$V_{H} = \frac{P_{H}}{M_{H}} = \frac{1.046 \times 10^{- 27}}{1.66 \times 10^{- 27}} = 0.63 m s^{- 1}$

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Monochromatic light of wavelength 632.8 nm is produced by a helium-neon laser. The power emitted is 9.42mW.How fast does a hydrogen atom have to travel in order to have the same momentum as that of the photon?

Given 1a.m.u.=1.66×10−27,PH=1.046×10−27The required speed of the hydrogen atom,VH=PHMH=1.046×10−271.66×10−27=0.63ms−1

Monochromatic light of wavelength $632.8$ nm is produced by a helium-neon laser. The power emitted is $9.42 m W$ .
How fast does a hydrogen atom have to travel in order to have the same momentum as that of the photon?

Given $1 a . m . u . = 1.66 \times 10^{- 27}, P_{H} = 1.046 \times 10^{- 27}$
The required speed of the hydrogen atom,
$V_{H} = \frac{P_{H}}{M_{H}} = \frac{1.046 \times 10^{- 27}}{1.66 \times 10^{- 27}} = 0.63 m s^{- 1}$