Method of Substitution to Find the Solution of a Pair of Linear Equations
Monthly incom...
Question
Monthly incomes of Aand B are in the ratio of 4 : 3 and their savings are in ratio of 3 : 2. If the expenditure of each will be Rs.600, what will be the monthly income of B ?
A
2400
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B
1170
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C
1500
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D
1800
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Solution
The correct option is C 1800 Income = Expenditure + Savings Let there Incomes are 4x and 3x and there savings are 3y and 2y Hence for A: 4x=3y+600 And for B: 3x=2y+600 Therefore, 4x−3y=600 ...(i) and 3x−2y=600 ...(ii) From eqn. (i) and (ii) ⇒4x−3y=3x−2y ⇒x=y ∴4x−3x=600 ⇒x=600 Then, the income of A=4×600=Rs.2400 and income of B=3×600=Rs.1800