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एक से अधिक उत्तर प्रकार के प्रश्न

The current I in an inductor is given by relation I = (5 + 10 t) A, where t is in second. The self-induced emf in it is 10 mV at t = 1 s. Then

किसी प्रेरक में धारा I को सम्बन्ध I = (5 + 10 t) A द्वारा व्यक्त किया जाता है, जहाँ t सेकण्ड में है। t = 1 s पर इसमें स्व-प्रेरित वि.वा.ब. 10 mV है। तब

A
Self-inductance of inductor is 1 mH

प्रेरक का स्व-प्रेरकत्व 1 mH है
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B
Increase in energy stored in inductor from t = 0 s to t = 1 s is 100 mJ

t = 0 s से t = 1 s तक प्रेरक में संग्रहित ऊर्जा में वृद्धि 100 mJ है
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C
The rate of energy stored in the inductor at t = 1 s is 150 mJ

t = 1 s पर प्रेरक में संग्रहित ऊर्जा की दर 150 mJ है
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D
Flux linked to inductor at t = 1 s is 30 mWb

t = 1 s पर प्रेरक से सम्बद्ध फ्लक्स 30 mWb है
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Solution

The correct option is C The rate of energy stored in the inductor at t = 1 s is 150 mJ

t = 1 s पर प्रेरक में संग्रहित ऊर्जा की दर 150 mJ है
Solution <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> ANTHE-2021 : Regular Medical(Repeater) Course for NEET(14-12-2021)

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