More than One Answer Type
एक से अधिक उत्तर प्रकार के प्रश्न

Two particles A and B are projected from ground at t = 0 with velocities as indicated. If they collide in mid air at t = t₀, then

दो कणों A तथा B को t = 0 पर धरातल से दर्शाए गए वेगों से प्रक्षेपित किया जाता है। यदि ये t = t₀ पर ऊपर की ओर वायु में टकराते हैं, तब

v₀ = 20 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

v₀ = 25 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

t₀ = 1 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

t₀ = 2 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C t₀ = 1 s
Solution

Suggest Corrections

Similar questions

The correct statement with regard to $H_{2}^{+}$ & $H_{2}^{-}$ is

40 m/s

50 m

H_{1}, H_{2}

2 H . M^{'} . s

a

b

\frac{H_{1} + H_{2}}{H_{1}, H_{2}} =

Join BYJU'S Learning Program