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Value of k if $f (x) = {\begin{matrix} {(1 + x)}^{\frac{1}{sin x}}, & x \neq 0 k, & x = 0 \end{matrix}$ is continuous at x = 0

यदि x = 0 पर $f (x) = {\begin{matrix} {(1 + x)}^{\frac{1}{sin x}}, & x \neq 0 k, & x = 0 \end{matrix}$ सतत है, तब k का मान है

ln(e^e)

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e^lne

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(lne)^e

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The correct option is C e^lne
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