Moses deposited Rs. $850$ into the bank in July. From July to December, the amount of money he deposited into the bank increase by $25 %$ per month. Whats the total amount of money in his account after December?

6570

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7570

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8570

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9570

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Solution

The correct option is D $9570$
To find the sum of the first $S_{n}$ terms of a geometric sequence use the formula,
Given, $a = 850, r = 1.25, n = 6$
$S_{n} = \frac{a_{1} (r^{n} - 1)}{r - 1}$
$S_{6} = \frac{850 ({1.25}^{6} - 1)}{1.25 - 1}$
$= \frac{2392.4926}{0.25}$
Therefore, $S_{6} \approx 9570$

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Moses deposited Rs. 850 into the bank in July. From July to December, the amount of money he deposited into the bank increase by 25% per month. Whats the total amount of money in his account after December?

The correct option is D 9570To find the sum of the first Sn terms of a geometric sequence use the formula,Given, a=850,r=1.25,n=6Sn=a1(rn−1)r−1S6=850(1.256−1)1.25−1=2392.49260.25Therefore, S6≈9570

Moses deposited Rs. $850$ into the bank in July. From July to December, the amount of money he deposited into the bank increase by $25 %$ per month. Whats the total amount of money in his account after December?

The correct option is D $9570$
To find the sum of the first $S_{n}$ terms of a geometric sequence use the formula,
Given, $a = 850, r = 1.25, n = 6$
$S_{n} = \frac{a_{1} (r^{n} - 1)}{r - 1}$
$S_{6} = \frac{850 ({1.25}^{6} - 1)}{1.25 - 1}$
$= \frac{2392.4926}{0.25}$
Therefore, $S_{6} \approx 9570$