MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Loudness

Most people i...

Question

Most people interpret a 9.0 dB increase in sound intensity level as a doubling in loudness. By what factor must the sound intensity be increased to double the loudness ?

Open in App

Solution

$S L = 10 l o g_{10} (\frac{I}{I_{0}})$
here, $9 = 10 l o g_{10} (\frac{2 I}{I_{0}})$
or $l o g_{10} (\frac{2 I}{I_{0}}) = 0.9$
$∴ \frac{2 I}{I_{0}} = 10^{0.9} = 7.9 \approx 8$

Suggest Corrections

thumbs-up

0

Similar questions

Q. By what factor must the sound intensity be increased to increase the sound intensity level by 13.0 dB ?

Q. Assertion :A

80 d B

sound has twice the intensity of a

40 d B

sound. Reason: Loudness of a sound of a certain intensity I is defined as

L_{d B} = 10 {log}_{10} {\frac{I}{I}}_{o}

Q. Assertion :Sound level increases linearly with intensity of sound. Reason: If intensity of sound is doubled sound level increases approximately 3 dB.

Q. A sound absorber decreases a sound's loudness from 60 dB to 20 dB. Intensity of sound decreases by a factor of

Q. The power , or loudness, of sound is measured on a scale of increased by a factor of 100

(= 10^{2}

), the sound is called twice as loud and when it increases 10,000

(= 10^{4})

times it is called four times as loud. The exponent of ten is called a bel and one decible is one tenth of a bel. Zero decible is chosen as the intensity of the slowest sound which is just audible or is on the threshold of hearing whereas the intensity of loudest sound is about 170 decibel. Sound intensities above a level of nearly descibels produce a feeling of pain :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Loudness

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard VIII Physics

Join BYJU'S Learning Program

CrossIcon