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Question

Most stable carbocation formed from (CH3)3CBr,(C6H5)3CBr,(C6H5)2CHBr and C6H5CH2Br would be:

A
C6H5CH2
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B
(CH3)3C
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C
(C6H5)3C
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D
(C6H5)2CH
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Solution

The correct option is C (C6H5)3C
Most stable carbocation formed will be (C6H5)3C obtained from the hydrolysis of (CH3)3CBr,(C6H5)3CBr,(C6H5)2CHBr.
This is because triphenyl methyl carbocation (C6H5)3C+ is highly stable due to delocalization of positive charge on three phenyl groups.
(C6H5)3CBr(C6H5)3C+
275676_281924_ans.png

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