Most stable carbocation formed from (CH3)3C−Br,(C6H5)3CBr,(C6H5)2CHBr and C6H5CH2Br would be:
A
C6H5⊕CH2
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B
(CH3)3⊕C
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C
(C6H5)3⊕C
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D
(C6H5)2⊕CH
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Solution
The correct option is C(C6H5)3⊕C Most stable carbocation formed will be (C6H5)3⊕C obtained from the hydrolysis of (CH3)3C−Br,(C6H5)3CBr,(C6H5)2CHBr. This is because triphenyl methyl carbocation (C6H5)3C+ is highly stable due to delocalization of positive charge on three phenyl groups. (C6H5)3CBr→(C6H5)3C+