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Question

Motion described by two different objects are shown in the figure. The ratio of accleration of the objects i.e. aAaB is

A
3:2
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B
5:3
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C
2:3
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D
3:5
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Solution

The correct option is C 2:3

We know that the acceleration of the object is the slope of vt curve
Therefore,
Acceleration of object A is given as aA=ΔvΔt=301530=5 m/s2
Similarly, Acceleration of object B is given as aB=ΔvΔt=30040=152 m/s2
Hence, the ratio is given as
aAaB=5152=23, i.e. 2:3

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