Motion described by two different objects are shown in the figure. The ratio of accleration of the objects i.e. aAaB is
A
3:2
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B
5:3
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C
2:3
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D
3:5
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Solution
The correct option is C2:3
We know that the acceleration of the object is the slope of v−t curve
Therefore,
Acceleration of object A is given as aA=ΔvΔt=30−153−0=5m/s2
Similarly, Acceleration of object B is given as aB=ΔvΔt=30−04−0=152m/s2
Hence, the ratio is given as aAaB=5152=23, i.e. 2:3