Motion of particle of mass M is described by Y=ut+1/2bt2 . Find the force acting on the particle.

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Solution

y = ut + 1/2 gt2

dy/dt = d/dt ut + d/dt 1/2 gt2

v= u + 2gt

dv/dt = d/dt u + d/dt 2gt

a = 0 + 2g

a = 2g

acceleration of particle =a =2g

mass of particle = m [Given]

Force = mass * acceleration

F = m * 2g

F = 2gm

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Motion of particle of mass M is described by Y=ut+1/2bt2 . Find the force acting on the particle.

y = ut + 1/2 gt2 dy/dt = d/dt ut + d/dt 1/2 gt2 v= u + 2gt dv/dt = d/dt u + d/dt 2gt a = 0 + 2g a = 2g acceleration of particle =a =2g mass of particle = m [Given] Force = mass * acceleration F = m * 2g F = 2gm

y = ut + 1/2 gt2

dy/dt = d/dt ut + d/dt 1/2 gt2

v= u + 2gt

dv/dt = d/dt u + d/dt 2gt

a = 0 + 2g

a = 2g

acceleration of particle =a =2g

mass of particle = m [Given]

Force = mass * acceleration

F = m * 2g

F = 2gm