Question

Motion of two objects are shown in the figure, which object has greater acceleration?

• A. $A$
• B. $B$
• C. Both have equal acceleration
• D. Can't say

Answer 1

The correct option is A $A$

We know that the acceleration of the object is the slope of $v-t$ curve
Therefore,
Acceleration of object $A$ is given as $a_A=\frac{\Delta v}{\Delta t}=\frac{30-0}{2-0}=15{\text{m/s}}^2$
Similarly, Acceleration of object $B$ is given as $a_B=\frac{\Delta v}{\Delta t}=\frac{20-0}{4-0}=5{\text{m/s}}^2$
Hence, the acceleration of object $A$ is greater than object $B$