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Question

Motorcycle rider is moving in a hollow sphere in a horizontal circle of radius 5 m with constant speed 12 m/s. Acceleration due to gravity is 9.8 m/s2. The coefficient friction between tires of the motorcycle and the inner surface of the sphere is:

A
2.94
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B
0.58
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C
0.34
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D
0.23
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Solution

The correct option is C 0.34
Here normal force will provide centripetal acceleration to move in horizontal circle
N=mrω2

In vertical direction net force should be 0
f=mg
μN=mg
μmrω2=mg
μ=g/rω2
μ=
μ=gr/v2
μ=0.34








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