Moving with uniform acceleration a body covers $150 m$ in $10 s$ , so that it covers $24 m$ during the tenth second. Then the acceleration of the body is

2 m / s^{2}

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3 m / s^{2}

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4 m / s^{2}

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6 m / s^{2}

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Solution

The correct option is A $2 m / s^{2}$
Using the equations of motion
s $= u t + \frac{1}{2} a t^{2}$
$150 = u \times 10 + \frac{1}{2} a \times 10^{2}$
$15 = u + 5 a \to e q u a t i o n (1)$
Distance travelled in n th second is given by the formula
$s_{n} = u + \frac{a}{2} (2 n - 1)$
$24 = u + \frac{a}{2} (19) \to e q u a t i o n (2)$
equation 2 $-$ equation 1 ,
$9 = \frac{9 a}{2}$
Thus, the acceleration, a $= 2 m / s^{2}$

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Moving with uniform acceleration a body covers 150m in 10s, so that it covers 24m during the tenth second. Then the acceleration of the body is

The correct option is A 2m/s2Using the equations of motions=ut+12at2150=u×10+12a×10215=u+5a→equation(1)Distance travelled in n th second is given by the formulasn=u+a2(2n−1)24=u+a2(19)→equation(2)equation 2 − equation 1 , 9=9a2Thus, the acceleration, a =2m/s2

Moving with uniform acceleration a body covers $150 m$ in $10 s$ , so that it covers $24 m$ during the tenth second. Then the acceleration of the body is