Mr Brijlal used flooring tiles of the shape of a parallelogram whose base is $13 m$ and the corresponding height is $7 m$ . How many such tiles are required to cover a floor of the hall, if its area is $62062 m^{2}$ ?

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Solution

REF.image
Total one of floor $= 62062 m^{2}$
Length of base of tile = 13 m
Height of tile = 7 m
Now, area of parallelogram of 1 tile
$13 \times 7$
$91 m^{2}$
Total No. of tiles used $= \frac{62062}{91}$
$= 682 A n s$

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Mr Brijlal used flooring tiles of the shape of a parallelogram whose base is 13 m and the corresponding height is 7 m. How many such tiles are required to cover a floor of the hall, if its area is 62062 m2?

REF.imageTotal one of floor =62062m2Length of base of tile = 13 mHeight of tile = 7 mNow, area of parallelogram of 1 tile 13×791m2Total No. of tiles used =6206291=682Ans

Mr Brijlal used flooring tiles of the shape of a parallelogram whose base is $13 m$ and the corresponding height is $7 m$ . How many such tiles are required to cover a floor of the hall, if its area is $62062 m^{2}$ ?

REF.image
Total one of floor $= 62062 m^{2}$
Length of base of tile = 13 m
Height of tile = 7 m
Now, area of parallelogram of 1 tile
$13 \times 7$
$91 m^{2}$
Total No. of tiles used $= \frac{62062}{91}$
$= 682 A n s$