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Question

Mr. Dubey borrows 100000 fro State Bank of India at 11% per annum compound interest . He repays 41000 at the end of first year and 47700 at the end of second year. Find the amount outstanding at the beginning of the third year.

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Solution

It is given that
Borrowed money (P) = 1000000
Rate = 11% p.a
Time = 1 year
We know that
Amount after first year = Prt/100
Substituting the values
= 100000+11000
= 111000
Amount paid at the end of first year = 41000
So the principal for second year = 111000 - 41000
= 70000
We know that
Amount after second year = P+(70000×11)/100
By further calculation
= 70000+700
= 77700
So the amount paid at the end of second year = 47700
Here the amount outstanding at the beginning year = 7770047700
=30000

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