Let the distance between his house & office = d km
If his speed is 20 kmph time taken =d20hrs
=d20×60 minus=3d minuts
30 kmph time taken =d30×60 =2d minuts
Correct time to reach office = 3d - 10 = 2d + 5 = t
d = 15 km
∴ The correct speed =dt=1535 km/min=/153/357×60 km/hr=1807=25.71 km/hr