Mr. Gidwani's Padyatra party wanted to go from Gwalior to Bhubaneswar. The walkers traveled $150$ km straight and then took a $45^{0}$ turn towards Varanasi and walked straight to another $120$ km. Approximately, how far was the party from the starting point?

250

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Solution

The correct option is C $250$ km
See the image
Since
$c o s (135^{o})$ = $\frac{A B^{2} + B C^{2} - A C^{2}}{2 \times A B \times B C}$
$∴$ $A C = \sqrt{(150)^{2} + (120)^{2} - 2 \times 150 \times 120 \times c o s (135^{0})}$
$= 250$ km.

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Mr. Gidwani's Padyatra party wanted to go from Gwalior to Bhubaneswar. The walkers traveled 150 km straight and then took a 450 turn towards Varanasi and walked straight to another 120 km. Approximately, how far was the party from the starting point?

The correct option is C 250 kmSee the imageSince cos(135o) = AB2+BC2−AC22×AB×BC∴ AC=√(150)2+(120)2−2×150×120×cos(1350)=250 km.

Mr. Gidwani's Padyatra party wanted to go from Gwalior to Bhubaneswar. The walkers traveled $150$ km straight and then took a $45^{0}$ turn towards Varanasi and walked straight to another $120$ km. Approximately, how far was the party from the starting point?

The correct option is C $250$ km
See the image
Since
$c o s (135^{o})$ = $\frac{A B^{2} + B C^{2} - A C^{2}}{2 \times A B \times B C}$
$∴$ $A C = \sqrt{(150)^{2} + (120)^{2} - 2 \times 150 \times 120 \times c o s (135^{0})}$
$= 250$ km.