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Question

Mr. Kumar drives to work at an average speed of 48 km per hour. The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance. How far is his office?

A
30 km
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B
40 km
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C
45 km
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D
48 km
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Solution

The correct option is C 40 km
Let the total distance be xkm.
Time taken to cover remaining 40% of x distance T1=40×x100×48
But given time taken to cover first 60% of x distance is T2=T1+1060hrs
T2=60×x100×48

60×x100×48=40×x100×48+1060

60×x100×4840×x100×48=1060

20x4800=1060

x=1060×480020

x=40km

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