Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of $14 %$ p.a. and $11 %$ p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? [4 MARKS]

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Solution

Concept : 1 Mark
Application : 1 Mark
Calculation : 2 Marks

Let the sum invested in scheme A be Rs. $x$ and that in scheme B be Rs. $(13900 - x) .$

Then, $\frac{x \times 14 \times 2}{100} + \frac{(13900 - x) \times 11 \times 2}{100} = 3508$

$\Rightarrow 28 x - 22 x = 350800 - (13900 \times 22)$

$\Rightarrow 6 x = 45000$

$\Rightarrow x = 7500.$

So, sum invested in Scheme B is

$= R s . (13900 - 7500) = R s . 6400.$

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Mr. Thomas invested an amount of ₹ 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be ₹ 3508, what was the amount invested in Scheme B?

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Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? [4 MARKS]

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of $14 %$ p.a. and $11 %$ p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? [4 MARKS]