Question

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a.respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B ?

• A. $Rs.6400$
• B. $Rs.6500$
• C. $Rs.7200$
• D. $Rs.7500$

Answer 1

The correct option is A $Rs.6400$

Let the investment in scheme $A$ be $Rs.x$

and the investment in scheme B be Rs.$(13900-x)$

We know that $SI=\frac{P\times R\times T}{100}$

Simple Interest for Rs.x in 2 years at 14% p.a $=\frac{x\times 14\times 2}{100}=\frac{28x}{100}$

Simple Interest for Rs.$(13900-x)$ in $2$ years at $11\%$ p.a.$=\frac{(13900-x)\times 11\times 2}{100}=\frac{22(13900-x)}{100}$

$Totalinterest=Rs.3508$

$\Rightarrow \frac{28x}{100}+\frac{22(13900-x)}{100}=3508$

$\Rightarrow 28x+305800-22x=350800$

$\Rightarrow 6x=45000\Rightarrow x=\frac{45000}{6}$

$\Rightarrow x=7500$

Investment in Scheme $B$ $=13900-7500=6400Rs$