Mr. Tiwari receives Rs 6455 at the end of one year at the rate of 14% per annum in a recurring deposit account. What is his monthly installment?
Rs 500
Suppose Mr. Tiwari deposited Rs 100 per month, P = Rs 100
Since the number of months (n) = 12 and rate of interest (r) = 14%
Interest (I) = P × n(n+1)/(2×12) × r/100
= Rs 100 × (12×13)/(2×12) × 14/100 = Rs 91
As the money deposited in 12 months = 12 × Rs 100 = Rs 1200
Maturity value = Rs (1200 + 91) = Rs 1291
By applying unitary method, we get:
When the maturity value is Rs 1291, monthly installment = Rs 100
When the maturity value is Rs 6455, monthly installment = Rs 100/1291 × 6455 = Rs 500.