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Question

Mr. Tiwari receives Rs 6455 at the end of one year at the rate of 14% per annum in a recurring deposit account. What is his monthly installment?


A

Rs 400

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B

Rs 500

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C

Rs 800

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D

Rs 700

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Solution

The correct option is B

Rs 500


Suppose Mr. Tiwari deposited Rs 100 per month, P = Rs 100

Since the number of months (n) = 12 and rate of interest (r) = 14%

Interest (I) = P × n(n+1)/(2×12) × r/100

= Rs 100 × (12×13)/(2×12) × 14/100 = Rs 91

As the money deposited in 12 months = 12 × Rs 100 = Rs 1200

Maturity value = Rs (1200 + 91) = Rs 1291

By applying unitary method, we get:

When the maturity value is Rs 1291, monthly installment = Rs 100

When the maturity value is Rs 6455, monthly installment = Rs 100/1291 × 6455 = Rs 500.


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