Mrs. Jhaluka deposits ₹1000 every month in a recurring deposit account for a time period of 3 years at 8% interest per annum. What is the Maturity Amount?
₹40,440
Monthly installment = ₹1000
Number of Months = 3 x 12 = 36 Months
Amount deposited = 1000 × 36 = ₹ 36000
Rate of interest = 8 %
Interest I = P × n×(n+1)2× 12 × r100
= 1000 × 36×(36+1)2× 12 × 8100
Interest = ₹4440
Maturity Value = Amount deposited + Interest
Amount on maturity = ₹ (36000 + 4440) = ₹40,440