mrs Razdan wants to use tiles of length 20 cm and breadth 10 cm to cover the floor of hger balcony shown in the figure.What is the area of the balcony?How many tiles does she neeed to buy (1sq m = 10,000 sq cm)?

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Solution

Area of balcony $= A r (1) + A r (2) + A r (3)$
$= (2 \times 4) + (2 \times 2) + (4 \times 2)$
$= 8 + 4 + 8 = 20 m^{2}$
Area of one tile $= 20 \times 10 c m^{2}$
$\Rightarrow$ Number of tiles $= \frac{20 \times 10^{4} c m^{2}}{20 \times 10 c m^{2}} = 10^{3}$ .

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mrs Razdan wants to use tiles of length 20 cm and breadth 10 cm to cover the floor of hger balcony shown in the figure.What is the area of the balcony?How many tiles does she neeed to buy (1sq m = 10,000 sq cm)?

Area of balcony=Ar(1)+Ar(2)+Ar(3)=(2×4)+(2×2)+(4×2)=8+4+8=20m2Area of one tile=20×10cm2⇒ Number of tiles=20×104cm220×10cm2=103.

Area of balcony $= A r (1) + A r (2) + A r (3)$
$= (2 \times 4) + (2 \times 2) + (4 \times 2)$
$= 8 + 4 + 8 = 20 m^{2}$
Area of one tile $= 20 \times 10 c m^{2}$
$\Rightarrow$ Number of tiles $= \frac{20 \times 10^{4} c m^{2}}{20 \times 10 c m^{2}} = 10^{3}$ .