$M S O_{4}$ is the formula of sulphate of metal M. Write down the formula of its :
i) Hydroxide ii) Chlorite iii) Chloride
iv) Nitrate v) Nitrite vi) Peroxide
vii) Chromate viii) Phosphate.

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Solution

For given formula of sulphate of metal, its valency is $+ 2$ .
(i) $O H^{-}$ is hydroxide ion. By balancing charge, formula of metal hydroxide ion is $M (O H)_{2}$ .
(ii) $C l O_{2}^{-}$ is chlorite ion. We need $2$ such ions for charge balance. Hence metal chlorite $M (C l O_{2}) 2$ .
(iii) Chloride has $C l^{-}$ ion. Hence, metal chloride is $M C l_{2}$ .
(iv) $N O_{3}^{-}$ is nitrate ion. By charge balance, metal nitrate is $M (N O_{3})_{2}$ .
(v) $N O_{2}^{-}$ is nitrite ion. Hence $M (N O_{2})_{2}$ is metal nitrite.
(vi) Peroxide has $O^{-}$ ion. By charge balance, metal peroxide is $M O_{2}$ .
(vii) $C r O_{4}^{2 -}$ is chromate ion. Hence, by balancing charges metal chromate is $M (C r O_{4})$ .
(viii) $(P O_{4})^{3 -}$ is phosphate ion. By charge balance, metal phosphate is $M_{3} (P O_{4})_{2}$ .

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MSO4 is the formula of sulphate of metal M. Write down the formula of its : i) Hydroxide ii) Chlorite iii) Chloride iv) Nitrate v) Nitrite vi) Peroxide vii) Chromate viii) Phosphate.

$M S O_{4}$ is the formula of sulphate of metal M. Write down the formula of its :
i) Hydroxide ii) Chlorite iii) Chloride
iv) Nitrate v) Nitrite vi) Peroxide
vii) Chromate viii) Phosphate.