MSO 4 NH 4 OH - white X excess NH 4 OH - Y H 2 S - Z - Here M and Z are-A- Cu - ZnSB- Zn - ZnSC- Fe- FeSD- Al - Al 2 S 3

The correct option is B Zn, ZnS ZnSO_4 White pptZn(OH)_2↓Soluble complex[Zn(NH_3)_4]^2+ (aq) White pptZnS ↓ ...

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Ammonia

MSO 4 NH 4 OH...

Question

$M S O_{4} N H_{4} O H - ---- \to ↓ X w h i t e N H_{4} O H - ---- \to e x c e s s Y H_{2} S - - \to ↓ Z .$ Here M and Z are:

Cu, ZnS

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Zn, ZnS

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Fe, FeS

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Al, Al₂S₃

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Solution

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M S O_{4} {N H}_{4} O H - ---- \to ↓ X w h i t e {N H}_{4} O H - ---- \to e x c e s s Y H_{2} S - - \to ↓ Z

M

Z

A l, C u, F e, M g

Z n

E_{A l^{3} + / A l}^{0} + - 1.66 V, E_{C u^{2} + / C u}^{0} = + 0.34 V

E_{F e^{2} + / F e}^{0} = - 0.44 V, E_{M g^{2} + / M g}^{0} = - 1.40 V

E_{Z n^{2} + / Z n}^{0} = - 0.76 V

For cell reaction, $Z n + C u^{2 +} \to Z n^{2 +} + C u,$ cell representation is

What will happen when metals such as Zn, Fe, Cu and Al react with nitric acid?

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