- 2-1- 2- 79 find - -1-

μ ^2+1/μ=79 now we know (μ +1/μ)^2 #160; = μ^2+1/μ^2+2μ×1/μ (μ+1/μ)^2 #160; = 79+2=81 μ+1/μ #160; =√(81) = 9 [μ+1/μ=± 9] ...

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Byju's Answer

Standard VII

Mathematics

Cardinality of Sets

μ 2+1/μ 2= 79...

Question

$μ^{2} + \frac{1}{μ^{2}} = 79$
find $μ + \frac{1}{μ}$

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Solution

$μ^{2} + \frac{1}{μ} = 79$
now we know
$(μ + \frac{1}{μ})^{2} = μ^{2} + {\frac{1}{μ}}^{2} + 2 μ \times \frac{1}{μ}$
$(μ + \frac{1}{μ})^{2} = 79 + 2 = 81$
$μ + \frac{1}{μ} = \sqrt{81} = 9$
$[μ + \frac{1}{μ} = \pm 9]$

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μ2+1μ2=79 find μ+1μ

μ2+1μ=79now we know(μ+1μ)2=μ2+1μ2+2μ×1μ(μ+1μ)2=79+2=81μ+1μ=√81=9[μ+1μ=±9]

$μ^{2} + \frac{1}{μ^{2}} = 79$
find $μ + \frac{1}{μ}$

$μ^{2} + \frac{1}{μ} = 79$
now we know
$(μ + \frac{1}{μ})^{2} = μ^{2} + {\frac{1}{μ}}^{2} + 2 μ \times \frac{1}{μ}$
$(μ + \frac{1}{μ})^{2} = 79 + 2 = 81$
$μ + \frac{1}{μ} = \sqrt{81} = 9$
$[μ + \frac{1}{μ} = \pm 9]$