$μ$ = {a, b, c, d, e, f, g, h, i, j}
P = {a, b, c, e}.
Q = {b, c, d, f} and
R = {c, f, h, i, j}
Number of elements of the set $(P \cap Q) \cup (P \cap R)$ is

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Solution

$(P \cap Q) \cup (P \cap R) = P \cap (Q \cup R)$
$Q \cup R = {b, c, d, f, h, i, j}$
$P \cap (Q \cup R) = {b, c}$
$\Rightarrow n (P \cap (Q \cup R)) = 2$

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