Multiple bonds are not present in :

nitrogen

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oxygen

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diamond

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carbon dioxide

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Solution

The correct option is D diamond
Nitrogen, $N_{2}$ is $N \equiv N$ .
Oxygen, $O_{2}$ is $O = O$ .
In diamond, only single bonds are present.(see image)
Carbon dioxide, $C O_{2}$ is $O = C = O$ .

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Similar questions

O = C = O, O = S = O .

π

S O_{3}

p π - p π

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