Question

Multiple Correct Answers Type
All the particles thrown with same initial velocity would strike the ground.

• A. With same speed
• B. Simultaneously
• C. Time would be least for the particle thrown with velocity v downward i.e., particle $1$
• D. Time would be maximum for the particle $2$

Answer 1

Answer: (A), (C), (D)

The correct options are
A With same speed
C Time would be least for the particle thrown with velocity v downward i.e., particle $1$
D Time would be maximum for the particle $2$

$(KE+PE{)}_f=(KE+PE{)}_i$ in all situations.
Hence, $K{E}_f$ is also equal as $P{E}_f=0$. Hence all the particles collide with the same speed.
$-h=v{t}_1-\frac{1}{2}g{t}_1^2$ [for first particle] .... (i)
$-h=-v{t}_2-\frac{1}{2}g{t}_2^2$ [for second particle] .... (ii)
From Eq. (i) and Eq. (ii) $t_2>t_1$
$t_2=maximum,t_1=minimum$
i.e., option (c) and (d) are correct.