Question

Multiple the binomials.
$(\frac{3}{4}{a}^2+3b^2)$ and $4(a^2-\frac{2}{3}{b}^2)$

Answer 1

$(\frac{3}{4}{a}^2+3b^2)\ast 4(a^2-\frac{2}{3}{b}^2)$

$=\left(\frac{3a^2+12b^2}{4}\right)\times 4\left(\frac{3a^2-2b^2}{3}\right)$

$=3(a^2+4b^2)\frac{(3a^2-2b^2)}{3}$

$=(a^2+4b^2)(3a^2-2b^2)$

$=3a^4-2b^2{a}^2+12a^2{b}^2-8b^4$

$=3a^2+10a^2{b}^2-8b^4$