Multiply-10 3 a-2 b9 a2-6 a b-4 b2

(3a minus; 2b) (9a2 + 6ab + 4b2) = 3a(9a2 + 6ab + 4b2) minus; 2b(9a2 + 6ab + 4b2) = (3a times; 9a2) + (3a times; 6ab) + (3a times; 4b2) minus; ...

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Byju's Answer

Standard VII

Mathematics

Addition of Algebraic Expressions

Multiply:10 3...

Question

Multiply:

(10) (3a − 2b) (9a² + 6ab + 4b²)

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Solution

(3a − 2b) (9a² + 6ab + 4b²)
= 3a(9a² + 6ab + 4b²) − 2b(9a² + 6ab + 4b²)
= (3a × 9a²) + (3a × 6ab) + (3a × 4b²) − (2b × 9a²) − (2b × 6ab) − (2b × 4b²)
= 27a³ + 18a²b + 12ab² − 18a²b − 12ab² − 8b³
= 27a³ + (18a²b − 18a²b) + (12ab² − 12ab²) − 8b³
= 27a³ + 0 + 0 − 8b³
= 27a³ − 8b³

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Multiply: (10) (3a − 2b) (9a2 + 6ab + 4b2)

Multiply:

(10) (3a − 2b) (9a² + 6ab + 4b²)