Multiply-10 3 a-2 b9 a2-6 a b-4 b2

(3a minus; 2b) (9a2 + 6ab + 4b2) = 3a(9a2 + 6ab + 4b2) minus; 2b(9a2 + 6ab + 4b2) = (3a times; 9a2) + (3a times; 6ab) + (3a times; 4b2) minus; ...

You visited us 27 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Addition of Algebraic Expressions

Multiply:10 3...

Question

Multiply:

(10) (3a − 2b) (9a² + 6ab + 4b²)

Open in App

Solution

(3a − 2b) (9a² + 6ab + 4b²)
= 3a(9a² + 6ab + 4b²) − 2b(9a² + 6ab + 4b²)
= (3a × 9a²) + (3a × 6ab) + (3a × 4b²) − (2b × 9a²) − (2b × 6ab) − (2b × 4b²)
= 27a³ + 18a²b + 12ab² − 18a²b − 12ab² − 8b³
= 27a³ + (18a²b − 18a²b) + (12ab² − 12ab²) − 8b³
= 27a³ + 0 + 0 − 8b³
= 27a³ − 8b³

Suggest Corrections

Similar questions

Q. Multiply :

3 a b \times ({5 a}^{2} + {4 b}^{2})

Q. Multiply the polynomials:

(i) (2.5 a - 0.5 b) a n d (4 b^{2} - 8 a b)

(i i) (\frac{1}{9}) a^{2} + b c - 15 a n d (\frac{4}{7}) b^{2} + a b + 10

Multiply the polynomials:

$(i) (2.5 a - 0.5 b) a n d (4 b^{2} - 8 a b)$

$(i i) (\frac{1}{9}) a^{2} + b c - 15 a n d (\frac{4}{7}) b^{2} + a b + 10$ [2 MARKS]

Q. What must be subtracted from

3 a^{2} - 6 a b - 3 b^{2} - 1

to get

4 a^{2} - 7 a b - 4 b^{2}

Q. Factorize:

a^{2} + 4 b^{2} - 3 a + 6 b - 4 a b

Join BYJU'S Learning Program

Multiply: (10) (3a − 2b) (9a2 + 6ab + 4b2)

Multiply:

(10) (3a − 2b) (9a² + 6ab + 4b²)