Multiply: $(12 x^{2}) (4 y^{2}) (2 x) (z^{4}) (2 y^{3})$

192 (x^{3}) (y^{5}) (z^{4})

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12 (x^{3}) (y^{5}) (z^{4})

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192 (x^{3}) (y^{5}) (2 z^{4})

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192 (x^{3}) (z^{4})

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Solution

The correct option is A $192 (x^{3}) (y^{5}) (z^{4})$
$(12 x^{2}) (4 y^{2}) (2 x) (z^{4}) (2 y^{3})$
First: $(12) (4) (2) (2) = 192$
Then: $(x^{3}) (y^{5}) (z^{4})$
So, $(12 x^{2}) (4 y^{2}) (2 x) (z^{4}) (2 y^{3}) = 192 x^{3} y^{5} z^{4}$

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