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Question

Multiply (2a−7) and (2a−7).

A
4a228a+49
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B
4a2+28a+49
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C
2a2+28a+49
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D
2a228a+49
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Solution

The correct option is A 4a228a+49
(2a7)(2a7)
Using ,
(ab)2=a22ab+b2, we get the above equation.
=(2a7)2
=(2a)22×2a×7+72
=4a228a+49

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