Multiply -2x-2 - 6x - 10- by -x - y-2- -2x-3 - 12x-2y-2 - 6x-2 -xy-2 - 10y-2 - 10x2x-3 - 2x-2y-2 - 6x-2 - 16xy-2 - 10y-2 - 10x2x-3 - x-2y-2 - 6x-2 -6xy-2 - 10y-22x-3 - 2x-2y-2 - 6x-2 -6xy-2 - 10y-2 - 10x

The correct option is D 2x^3 + 2x^2y^2 6x^2 6xy^2 + 10y^2 + 10x(2x^2 6x + 10)× (x + y^2) = x(2x^2 6x + 10) + y^2(2x^2 6x + 10) = 2x^3 6x^2 + 10x + 2x ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Multiplication of a Binomial by a Trinomial

Multiply (2x^...

Question

Multiply $(2 x^{2} - 6 x + 10)$ by $(x + y^{2})$ .

2 x^{3} + 12 x^{2} y^{2} - 6 x^{2} - x y^{2} + 10 y^{2} + 10 x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 x^{3} + 2 x^{2} y^{2} - 6 x^{2} + 16 x y^{2} + 10 y^{2} + 10 x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 x^{3} + 2 x^{2} y^{2} - 6 x^{2} - 6 x y^{2} + 10 y^{2} + 10 x

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 x^{3} + x^{2} y^{2} - 6 x^{2} - 6 x y^{2} + 10 y^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2 x^{3} + 2 x^{2} y^{2} - 6 x^{2} - 6 x y^{2} + 10 y^{2} + 10 x$
$(2 x^{2} - 6 x + 10) \times (x + y^{2})$
= $x (2 x^{2} - 6 x + 10) + y^{2} (2 x^{2} - 6 x + 10)$
= $2 x^{3} - 6 x^{2} + 10 x + 2 x^{2} y^{2} - 6 x y^{2} + 10 y^{2}$
Rearranging the terms,
$2 x^{3} + 2 x^{2} y^{2} - 6 x^{2} - 6 x y^{2} + 10 y^{2} + 10 x$

Suggest Corrections

Similar questions

Q. Divide:
(i) 5m³− 30m² + 45m by 5m
(ii) 8x²y² − 6xy² + 10x²y³ by 2xy
(iii) 9x²y − 6xy + 12xy² by − 3xy
(iv) 12x⁴ + 8x³ − 6x² by − 2x²

Q. Factorise.

6 x^{2} - 11 x y - 10 y^{2}

Q. The value of

λ

, for which the equation

6 x^{2} + 11 x y - 10 y^{2} + x + 3 + y λ = 0

represents a pair of straight lines, is

Q. Solve

{lim}_{x \to 2} \frac{x^{3} - 6 x^{2} + 11 x - 6}{x^{2} - 6 x + 8}

Q. Evaluate :

{lim}_{x \to 2} \frac{x^{3} - 6 x^{2} + 11 x - 6}{x^{2} - 6 x + 8}

Join BYJU'S Learning Program

Multiply (2x2−6x+10) by (x+y2) .

The correct option is C 2x3+2x2y2−6x2−6xy2+10y2+10x(2x2−6x+10)×(x+y2) = x(2x2−6x+10)+y2(2x2−6x+10) = 2x3−6x2+10x+2x2y2−6xy2+10y2 Rearranging the terms, 2x3+2x2y2−6x2−6xy2+10y2+10x

Multiply $(2 x^{2} - 6 x + 10)$ by $(x + y^{2})$ .