1
Question
Multiply 3+2√2×3-2√2
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Solution
Let
a = 3
b= 2√2
using
a^2 - b^2 = (a+b)(a-b)
ie
.(3+2√2)×(3- 2√2)
3^2-(2√2)^
=9-8
=1
a = 3
b= 2√2
using
a^2 - b^2 = (a+b)(a-b)
ie
.(3+2√2)×(3- 2√2)
3^2-(2√2)^
=9-8
=1
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