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Byju's Answer
Standard IX
Mathematics
Expansion of (a ± b ± c)²
Multiply 99...
Question
Multiply
9999
by
999
Open in App
Solution
9999
×
999
=
(
10
,
000
−
1
)
×
(
1000
−
1
)
=
10000
(
1000
−
1
)
−
(
1000
−
1
)
=
1
,
00
,
00
,
000
−
10
,
000
−
1000
+
1
=
1
,
00
,
00
,
001
−
11
,
000
=
99
,
89
,
001
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1
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