CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Multiply 9x²+25y²+15xy+12x-20y+16 by 3x-5y-4 using suitable identity

Open in App
Solution

(3x-5y-4) (9x²+25y²+15xy+12x-20y+16)
⇒ (3x-5y-4) (9x²+25y²+16+15xy-20y+12x)
⇒ {3x + (-5y) + (-4)} {(3x)² + (-5y)² + (-4)² - (3x) (-5y) - (-5y) (-4) - (-4) (3x)}
⇒ (3x)³ + (-5y)³ + (-4)³ - 3 (3x) (-5y) (-4)
[As we know a³ + b³ + c³ - 3abc = (a + b + c) (a² + b² + c² -ab - bc - ca)]
= 27x³ - 125y³ - 64 - 180xy



flag
Suggest Corrections
thumbs-up
45
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
(x+a)(x+b)
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon