Multiply: $a b, a b$

a^{2} b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{2} b^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a b^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{3} b^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $a^{2} b^{2}$
$a b \times a b$
$= a^{1 + 1} \times b^{1 + 1}$
$= a^{2} b^{2}$

Suggest Corrections

Similar questions

Q. Multiply:

(8) (ab + a²b + ab²) (a + b)

Q. If

| a | < 1

and

| b | < 1

then

s = 1 + (1 + a) b + (1 + a + a^{2}) b^{2} + (1 + a + a^{2} + a^{3}) b^{3} + . . . i s - .

Q. If

| a | < 1

| b | < 1

, then the sum of the series

1 + (1 + a) b + (1 + a + a^{2}) b^{2} + (1 + a + a^{2} + a^{3}) b^{3} + . . . .

If x = 1 + a + $a^{2}$ .......... to $\infty$ (|a|<1), y = 1 + b + $b^{2}$ ......... to $\infty$ (|b| < 1), then Z = 1 + ab + $a^{2}$ $b^{2}$ + $a^{3}$ $b^{3}$ ..... to ∞ is

Q. Find the sum of the infinite series

1 + (1 + a) b + (1 + a + a^{2}) b^{2} + (1 + a + a^{2} + a^{3}) b^{3} + . . . . b

and a being proper fractions.

Join BYJU'S Learning Program

Multiply: ab,ab

The correct option is B a2b2ab×ab=a1+1×b1+1=a2b2

Multiply: $a b, a b$

The correct option is B $a^{2} b^{2}$
$a b \times a b$
$= a^{1 + 1} \times b^{1 + 1}$
$= a^{2} b^{2}$