Question

Multiply:

$\frac{2}{3}ab$ by $-\frac{1}{4}{a}^{2}b$

• A. $-\frac{1}{6}{a}^3{b}^3$
• B. $-\frac{1}{6}{a}^3{b}^2$
• C. $-\frac{1}{6}{a}^4{b}^2$
• D. $-\frac{1}{6}{a}^3{b}^4$

Answer 1

Answer: (B)

$\left(\frac{2}{3}ab\right)\times (-\frac{1}{4}{a}^{2}b)$

$=\frac{2}{3}\times -\frac{1}{4}\times a{a}^{2}bb$

$=\frac{1}{3}\times -\frac{1}{2}\times a^{1+2}{b}^{1+1}$ [Since, $x^m\times x^n=x^{m+n}$]

$=-\frac{1}{6}{a}^3{b}^2$

Hence, Option B is correct.