Multiply : (i) $3 x^{2}$ + 4xy by 2x (ii) – 4a [a + 3b]

Open in App

Solution

(i) 2x [ $3 x^{2}$ + 4xy] = $6 x^{3}$ + $8 x^{2}$ y
(ii) – 4a [a + 3b] = – 4 $a^{2}$ – 12ab

Suggest Corrections

Similar questions

(3 x^{2} - 2 x - 1)

(2 x^{2} + x - 5)

(x^{2} - 5 x + 2)

(3 x^{2} + 2 x - 5)

8 a b^{2}

- 4 a^{3} b^{4}

{(2 x - \frac{1}{3 x})}^{2}

{(3 x^{2} + 5 y)}^{2}

(\sqrt{2 x} - 3 y) (\sqrt{2 x} + 3 y)

{(\frac{1}{4} a - \frac{1}{2} b + 1)}^{2}

$F i r s t m o n o m i a l \to - --------------- \to ↓ S e c o n d m o n o m i a l$	2x	-5y	$3 x^{2}$	-4xy	$7 x^{2} y$	$- 9 x^{2} y^{2}$
2x	$4 x^{2}$	-	-	-	-	-
- 5y	-	-	$- 15 x^{2} y$	-	-	-
$3 x^{2}$	-	-	-	-	-	-
- 4xy	-	-	-	-	-	-
$7 x^{2} y$	-	-	-	-	-	-
$- 9 x^{2} y^{2}$	-	-	-	-	-	-

Join BYJU'S Learning Program