Question

Multiply :
$\left(i\right)\frac{5}{6}\text{and}\frac{8}{9}\left(ii\right)\frac{2}{7}\text{and}\frac{-14}{9}\left(iii\right)\frac{-7}{8}\text{and}4\left(iv\right)\frac{36}{-7}\text{and}\frac{-9}{28}\left(v\right)\frac{-7}{10}\text{and}\frac{-8}{15}\left(vi\right)\frac{3}{-2}\text{and}\frac{-7}{3}$

Answer 1

$\left(i\right)\frac{5}{6}\text{and}\frac{8}{9}=\frac{5\times 8}{6\times 9}=\frac{5\times 4}{3\times 9}=\frac{20}{27}\left(ii\right)\frac{2}{7}\text{and}\frac{-14}{9}=\frac{2\times (-14)}{7\times 9}=\frac{2\times (-2)}{1\times 9}=\frac{-4}{9}\left(iii\right)\frac{-7}{8}\text{and}4=\frac{(-7)\times 4}{8\times 1}=\frac{(-7)\times 1}{2\times 1}=\frac{-7}{2}=3\frac{1}{2}\left(iv\right)\frac{36}{-7}\text{and}\frac{-9}{28}=\frac{36\times (-9)}{(-7)\times 28}=\frac{9\times (-9)}{(-7)\times 7}=\frac{-81}{-49}=\frac{81}{49}=1\frac{32}{49}\left(v\right)\frac{-7}{10}\text{and}\frac{-8}{15}=\frac{(-7)\times (-8)}{10\times 15}=\frac{(-7)\times (-4)}{5\times 15}=\frac{28}{75}\left(vi\right)\frac{3}{-2}\text{and}\frac{-7}{3}=\frac{3\times (-7)}{(-2)\times 3}=\frac{1\times (-7)}{(-2)\times 1}=\frac{-7}{-2}=\frac{7}{2}=1\frac{1}{2}$