Question

Multiply:

iii) $6\frac{2}{3}$ and $\frac{-3}{8}$

Answer 1

Step 1: Converting the mixed fraction into
an improper fraction

Given : $6\frac{2}{3}=\frac{6\times 3+2}{3}=\frac{20}{3}$

Step: 2 Finding the product of given
numbers
$6\frac{2}{3}\times \frac{-3}{8}$
$=\frac{20}{3}\times \frac{-3}{8}$
Product of two rational numbers
$=\frac{Productofthenumerators}{Productofthedenominators}$
$=-\frac{20\times 3}{3\times 8}=-\frac{5\times 4\times 3}{3\times 4\times 2}=-\frac{5}{2}$
Hence, the required product is $-\frac{5}{2}$.